Zuhaib Nazir's blog

Dear Researchers 

I am trying to simulate hot compression test in ABAQUS with friction effect. In friction properties when coefficient of friction is changing from 0.1 to 1, there is no effect of curves for force vs. displacement. I have attached the graphs and result pictures file with this blog. What I understood as the friction plane is perpendicular to applied force thats why there will be no effect of friction coefficient value on force vs displacement graph.

Dear Researchers

Can you please make a correction in my Code of MATLAB

X1=[1,2,3,4]';

X2=[5,6,7,8]';

U1=[9,10,11,12]';

U2=[13,14,15,16]';

for i=1:1:4

EPS1(i,1)= U1(i,1)/X1(i,1);

EPS2(i,1)= U2(i,1)/X2(i,1);

EPS12(i,1)= 0.5*((U1(i,1)/X2(i,1))+(U2(i,1)/X1(i,1)));

defG(i)=[1+U1(i,1)/X1(i,1) 0+U1(i,1)/X2(i,1); 0+U2(i,1)/X1(i,1) 1+U2(i,1)/X2(i,1)];

end

EPS11

EPS22

EPS12

are right but for defoarmation gradient  i am getting error of 

Dear Researchers 

I have attach a text file with this message in which I have written all my code. I have applied the Radial Basis Function (interpolation) to find approximated displacements.

f = RBF(r)*a

f = given values e-g displacements to be approximate

RBF(r)= Radal Basis function (Thin Plate spline)

a= Radial Basis Function coefficient

X= x distance from the origin (given) (first column of disppoints)

Y= y distance from the origin (given)(second column of disppoints) For example as below

X    Y    f(U)

1    5    4