Energy problem is about to solve

The figure is in cross section. as shown in figure, there are two cases. in each case there are two pulleys of same diameter. each pulley is of exactly circular shape.In first case 50 k.g weight is fixed with each pulley as shown in figure. The center of each pulley is fixed. Between these two pulleys there is a stationary plate. plate will remain stationary, while rotating the pulleys because centers of pulleys are fixed. 100 k.g weight is put on this plate. The force or weight of plate is applied on these two pulleys in vertical downward direction. now we try to rotate slowly first pulley in clockwise direction and second pulley in anti clockwise direction. lubrication is provided between the contact surfaces of stationary plate and pulleys.
In second case two pulleys of same diameter. 50 k.g weight is also fixed with each pulley, but there is no stationary plate and 100 k.g weight. Now we try to rotate slowly first pulley in clockwise direction and second pulley in anti clockwise direction.
As free body diagram in first case we can rotate pulleys using less moment of force. we can lift mass using less energy.

1. In case 1) the moment necessary to rotate each pulley is

m=(-g/2cos(bita)+g1*cos(alpha))*r
where:
g is weight of plate (=100 kg)
g1 is given weight (=50 kg)
alpha and bita are angle of rotation of each pulley
r is radius of pulley
2. In case 2) weigt of plate g=0 Pl visit http://www.energyefficiency.zoomshare.com/