iMechanica - Comments for "Identifying fracture energy in ductile damage in ABAQUS"
https://imechanica.org/node/21045
Comments for "Identifying fracture energy in ductile damage in ABAQUS"enNow I figured out that it
https://imechanica.org/comment/28977#comment-28977
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<p><em>In reply to <a href="https://imechanica.org/node/21045">Identifying fracture energy in ductile damage in ABAQUS</a></em></p>
<div class="field field-name-comment-body field-type-text-long field-label-hidden"><div class="field-items"><div class="field-item even"><p>Now I figured out that it might have something to do with the characteristic length of the element. I thought this would be the thickness of the element (in this case 0.2), but apparently it's not that simple.</p>
<p>I found papers citing a relation proposed by Bazant and Oh: characteristic length L = sqr(A) / cos(theta), where A is the area associated with the integration point (I thought in this case is 1x1), and theta is the angle between the mesh line along which the crack band advances and the crack direction. This is where I get confused, as I just created a one-element model without specifying any crack line.</p>
<p>Even if I assume that this theta is zero, it would be u = ε * L = ε * 1 = 0.57, and with the equation before G would be G = 14.25, which is not the value I specified for the material.</p>
<p>So now the question: how do I get the characteristic length of my element?</p>
<p>Thank you in advance</p>
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</ul>Tue, 21 Mar 2017 16:38:40 +0000ndhaa26comment 28977 at https://imechanica.org