Dear friends,
I have a question which I posted in BLOGS section a week or so back. But I have no reply / comment from any reader of the blog.
So I am re-posting the same in this section ( FORUM) .
The query is as below ;
Generating MIST
from still water
How much velocity / acceleration (linear) is needed
to be imparted to water lying at rest (at atmospheric pressure) to convert it
into MIST ?
I know that Water is not
converted to mist by velocity or acceleration. It's
converted to mist by turbulent air flow on its
surface.
Re-phrasing a bit as ;
" I put water in open conduit (half pipe
section for example) and put it
on top of Bullet Train (assuming conduit is
welded to bullet train).
Now will the water Lump ( mass) split into fine
droplets (mist) ? "
Dear Friends, I am also
aware from my barbers shop that spray bottles can generate mist / mist-like phenomenon!
Hence, my question is
pertaining to CALCULATION ....!
If I consider the drag equation :-
F(drag) = 1/2 C*Rho*A*v^2 ;
where Rho = air density A = cross section area v
= velocity .
Problem No 1 ; is what profile should I
consider viz Speherical / Conic / Parabolic / irregular ? The value ranges from
0.5 to 2 according to SERWAY depending on the profile.
Problem
No 2 is
What to equate the F(drag) to ; Van der Waal's Forces or
Atomic Bond Forces ?
The F(drag) must be > the Structural Stablizing
force of the Water Bulk !
And Van der Waal's Eq in simple form ; (p+ a'/v^2
)(v-b') = kT; where a' = inter particle force, b= volume of particles, v= voulme
of container !! Considering p = 1 bar ( open to atmosphere) , T = (25deg C+ 273
) Kelvin & k = 0.008314.
Please help through this sequence of
thought process.
Regards,
Pipeyoga_011