**Calculate The Potential Difference Across Capacitor C1**

Physics: Calculate the total difference between each capacitor. ? ۔

I do not understand this question, please help me!

0.5V F and 1.4 F Capacitors (C1 and C2, respectively) are connected in series to form a 10V battery.

A) Calculate the total difference between each capacitor.

B) Calculate the charge on each capacitor.

C) Calculate the total difference between each capacitor that the two capacitors are parallel.

D) Calculate the charge of each capacitor if the two capacitors are parallel.

Since they are connected in series, each capacitor has the same charge Q. We know that usually Q = CV, so Q / C = V

NS:

Q / C1 + Q / C2 = 10V => QC1 + QC2 = 10C1C2 = 7e12 => Q = 7e12 (C1 + C2) = 3.68e6 C

A) Calculate the total difference between each capacitor.

a) Actually, the question does not have enough information to get the answer, unless we assume that two capacitors have been charged for s, so we assume this.

With series capacitors, any current that flows from one capacitor to another. Therefore, each capacitor must be charged the same amount. When this charge is Q1 or Q2, Q1 = Q2.

If it's advanced physics, you have a

Q = C * V (change in voltage, equal to the voltage since we started at 0)

Q1 = Q2.

C1 * Â V1 = C2 * Â V2.

0.5 V1 = 1.4 Â V2.

But you also know that ÂˆÂ V1 + V2 = 10 volts, battery.

Now you can solve both equations V1 and V2.

The electric motor will recognize the circuit as a capacitive divider and use only formulas like C1 * V / (C1 + C2) to find the voltage, but since this is physics, you need to understand the basic method. Is.

b) Once you find the voltage across the capacitor, reconnect it using the formula Q = CÃ ÂˆÂ V to find the charge. Keep an eye on your unit. Your answer must be in the '(C (microCoulomb) range. Another check is that if you add the equation to C1 or C2, you get the same value.

C) Once you understand what parallel means, it should be easy.

d) Use only the formula Q = C Â V ve.