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an epitaxial question

Submitted by Jian SHI on

Hi, everybody, i had one problem. see the attached image.

Does anyone know how to get the strain function or strain energy of the perfect epitaxial film? Or could you recommend some textbooks or references about this topic?

Thank you

Attachment Size
lattice mismatch.png 27.49 KB

Dear Professor Suo,

Thank you for your reply. I may not make my question clear. Here I try to make this question more clear:

 In detail, a cylinder-like simple cubic structure film (height: 500 nm; Diameter: 5nm) is epitaxial grown on a rigid simple cubic structure substrate without any defects except strain. I believe the strain along the radius direction is different: the core part should have a bigger strain than the shell part. Also, the strain along the axial direction is different: the part close the interface is larger than the outside part.

My question is: what is the strain field (strain function or strain distribution) along raidus and axial directions, respectively? An expotential function or others?

Thank you!

 

 

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Sat, 08/01/2009 - 06:10 Permalink

You are right, the object is more like a needle rather a perfect cylinder. People now have grown many single wires (called nanowires) vertically, heteroepitaxially and directly on substrates and attach is an image I got from a GaAs nanowire on Si (111) paper. See attach. Since people think islands combined film are the natural growth result. , this kinda phenomena is not expected before, right?

Instead of the top part, the lateral sides(surronding surfaces of the wire) could provide the relaxion. I am looking for a analytical solution for this strain or strain energy.

Attach: Here is one example: http://pubs.acs.org.ezproxy.library.wisc.edu/doi/full/10.1021/nl802062y

 

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Sun, 08/02/2009 - 09:52 Permalink

i just got the solution, actually, i got a equation group with 9 partial differential equations for this problem. If anyone is interested, take a look Timshenko 198x Theory of Elasticity, Chapter 8.

Sat, 08/22/2009 - 01:07 Permalink