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Shear Locking vs. Membrane Locking?

Submitted by Sacheen Bekah on

Could anyone briefly explain what is the difference between "Shear Locking" and "Membrane Locking". Does this apply to plain strain elements?

 Thank you.

Dear Sacheen,

Membrane locking

Membrane locking does only occur in curved beam and shell elements. The term describes a

stiffening effect that occurs if pure bending deformations (“inextensional bending”) are accompanied

by parasitic membrane stresses. It is sometimes confused with shear locking and

volumetric locking because these effect the membrane part of shell elements. However, they

are completely different phenomena.

As membrane locking is associated with the curvature of a structure it only occurs if the elements

are actually curved. For instance in the analysis of a cylindrical shell with four-node

elements there is no membrane locking when the mesh is aligned to the edges of the shell,

because the individual elements are flat. Linear triangles are always free from membrane

locking because they are always flat, regardless of the shape of the shell. Quadratic and biquadratic

elements usually show strong membrane locking in any situation.

Shear locking

Shear locking can occur in 2d and 3d solid elements as well as shell elements. The effect is

significant only if there is a certain (in-plane) “bending” deformation of the structure.

From a mathematical point of view, shear locking is not existent. Looking at the corresponding

differential equation, there is no ill-conditioning or “small parameter”. Actually, the critical

parameter in the case of shear locking is the aspect ratio of the element (i.e. no property of

the underlying mathematical problem itself). This can be understood most easily with the help

of an analogy to the Timoshenko beam element. The aspect ratio of a 2d solid element has the

same effect on the stiffness matrix as the length-to-thickness ratio in the beam element.

 

Further information

 

Martin J. Gross
www.matfem.de

Mon, 10/13/2008 - 08:03 Permalink

If you consider a beam with thickness t under combined shear and bending deformations, the portion of the internal energy associated with the bending deformation is proportional with t^3, but the portion related to shear deformations is proportional with t. Now if we reduce the thickness t, the value of t^3 approaches zero much faster than t and as a result, all the strain energy of the beam will come from shear deformation. This is not correct because for a thin beam it is always the bending deformations which provide most part of the energy. So the shear deformation beam can lead to wrong results for very thin beam. This is called shear locking.

Membrane locking happens when you model a curved surface of with flat (facet) shell elements. In this case because the elements are not in the same plane, bending vector of one element will have a projection on the next element which acts like an in-plane moment or drilling moment. Again in-plane deformations energy is proportional to t but bending energy is proportional to t^3 and the same problem happens when t becomes very small, i.e. membrane resistance of the next element stops bending deformation on this element. This is called membrane locking.

Peyman

Sat, 03/06/2010 - 15:51 Permalink

 

 

Hello all, in fact i'm studing the transverse shear locking for 3D elements (3D solid-shell elements) by analysing the subspace of null transverse shear strains applied for 2D elements but ,till now, not for 3D elements (so far as i know), but it's very difficule to know the basic components for the null transverse shear deformations, someone can help me ?? thanks in advance.

Tue, 07/17/2012 - 16:33 Permalink