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Unconditionally stable explicit method

Submitted by Pooyan Broumand on

Hi every one, 

I have recently seen some papers that claim to present an unconditionally stable explicit time integration method.

Is it (mathematically) possible to do such a thing?! I though that all explicit methods are atmost conditionally stable.

afallah

Dear pooyan

I worked on the linear multi-step methods which is one of the time integration methods. For this case there is a theorem that says it is impossible for an explicit multistep method to become A-stable (unconditionally stable), but it can be zero-stable(conditionally stable) . for others methods you can search in the numerical analysis reference books.

Tue, 01/13/2015 - 20:05 Permalink