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1. assuming to exist a PDE describing an equilibrium along one direction (e.g., postive direction along X coordinate), A+B=0;

2. after normalization process to the above PDE, we got, A*+(C)B*=0;

3. (C)=B/A, is the dimensionless number, and obviously, (C) implicits that both two effects arising from A and B are the same in the direction, i.e., along the X positive coordanate;

I have made video For explanation of cam follower prototype for clean energy cheaper than coal. You can find more information about my prototype at http://mechanicalresearch.info/

hello ,

i need simples codes MATLAB

in cohesive crack  under static  or dynamic load

 The Simplex K with 4 Vertices in Dimension 3 is a Tetrahedron and :

 K = determinant((x2-x1) , (x3-x2) , (x4-x3) ; (y2-y1) , (y3-y2) , (y4-y3) ; (z2-z1) , (z3-z2) , (z4-z3))

 The Volume of this element is :

 V(K) = abs(K) / 3! 

 If V(K) ~= 0  then K is Nearly Degenerated

 Moussaoui

Dear Abaqus user

I am modeling a post-tensioned concrete pier with 4 part:

-concrete foundation,pier,cap(C3D8R) and tendon(wire,B31)

 I input prestress force by predefined file,stress in initial step.The first step is static,General to find equilibrium.

 I embeded the beginning & the end of wire in foundation & cap. contact between (foundation,pier) & (pier,cap) is hard normal contact and the tangential behavior is penalty.