Ted Belytschko passed away
It is with great sadness that we post this entry. Ted Belytschko passed away early this morning, 15 September 2014.
It is with great sadness that we post this entry. Ted Belytschko passed away early this morning, 15 September 2014.
There is still time to apply the 5-year post-doctoral position at the University of Southampton. We are looking for a talented young researcher to join a group working on the definition of the next generation of high strain rate tests based on ultra-high speed deformation imaging and inverse identification (PhotoDyn project). Please apply online before September 30th.
These notes are writen for part of a course on plasticity.
These notes are part of a course on plasticity.
I am teaching this course this semester. I'll post notes as I write them. Links to the notes are listed in this post. I will also notify updates on twitter: https://twitter.com/zhigangsuo
I wrote these notes as a background for teaching elasticity and plasticity. Even in this most basic formulation, the dilation of the fluid is viscoelastic.
I am using Maxps Damage criteria for an XFEM crack for a three point bending case. I am using displacement loading on the specimen and wish to plot reaction load v/s mouth opening displacement. I would like to know how to obtain the crack tip opening displacement in ABAQUS. All the journal papers I read show a slump in reaction force after the crack starts to propagate. I plot the results and contour plots show me clearly that the crack has started to propagate. Please help.
We are no longer accepting appciations for this position.
Qulified applicants will be contacted soon.
Thank you for your interests again.
Dear reaserchers
Here is my question in developing the eqivalent strain via in-plane stress problems. please let me find your answers.
I did an experimental test on a 6 mm thickness plate. Principal strains (ε1,ε2) was developed from recorded strains via Rosset strain gauges . To develop the equivalent strains I need ε1 , ε2 , ε3 in the following eqation:
dεe=(√2/3)(dε12+dε22+dε32)1/2